2*0.8*p+0.64+p^2=1

Solution for 2*0.8*p+0.64+p^2=1 equation:

2*0.8p+0.64+p^2=1

We move all terms to the left:

2*0.8p+0.64+p^2-(1)=0

We add all the numbers together, and all the variables

p^2+2*0.8p-0.36=0

Wy multiply elements

p^2+0p-0.36=0

We add all the numbers together, and all the variables

p^2+p-0.36=0

a = 1; b = 1; c = -0.36;
Δ = b2-4ac
Δ = 12-4·1·(-0.36)
Δ = 2.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2.44}}{2*1}=\frac{-1-\sqrt{2.44}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2.44}}{2*1}=\frac{-1+\sqrt{2.44}}{2}
$